Sequence and SeriesMCQMTP June 24 Series IQuestion 1811 of 212
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If the sum of n\displaystyle n terms of an A.P. be 2n2+5n\displaystyle 2n^2+5n, then its 'nth\displaystyle n^{th}' term is:

Options

A4n2\displaystyle 4n-2
B3n4\displaystyle 3n-4
C4n+3\displaystyle 4n+3
D3n+4\displaystyle 3n+4
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Correct Answer

Option c4n+3\displaystyle 4n+3

All Options:

  • A4n2\displaystyle 4n-2
  • B3n4\displaystyle 3n-4
  • C4n+3\displaystyle 4n+3
  • D3n+4\displaystyle 3n+4

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Detailed Solution & Explanation

Given the sum of n\displaystyle n terms Sn=2n2+5n\displaystyle S_n = 2n^2 + 5n.
The nth\displaystyle n^{\text{th}} term tn\displaystyle t_n is:
tn=SnSn1t_n = S_n - S_{n-1}
tn=2n2+5n[2(n1)2+5(n1)]t_n = 2n^2 + 5n - [2(n-1)^2 + 5(n-1)]
tn=2n2+5n[2(n22n+1)+5n5]t_n = 2n^2 + 5n - [2(n^2 - 2n + 1) + 5n - 5]
tn=2n2+5n[2n24n+2+5n5]t_n = 2n^2 + 5n - [2n^2 - 4n + 2 + 5n - 5]
tn=2n2+5n2n2n+3=4n+3t_n = 2n^2 + 5n - 2n^2 - n + 3 = 4n + 3
Hence, **Option C** is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

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