Sequence and SeriesMCQPYQ Nov. 19Question 1825 of 212
All Questions

Sum up to infinity of series. 1+12+13+14+18+19+116+127+\displaystyle 1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{8} + \frac{1}{9} + \frac{1}{16} + \frac{1}{27} + \dots

Options

A1924\displaystyle \frac{19}{24}
B24/19\displaystyle 24/19
C5/24\displaystyle 5/24
DNone of these
For any discrepancies in this question, email contact@cadada.in

Correct Answer

Option dNone of these

All Options:

  • A1924\displaystyle \frac{19}{24}
  • B24/19\displaystyle 24/19
  • C5/24\displaystyle 5/24
  • DNone of these

Ad

Detailed Solution & Explanation

The series can be split into two separate infinite geometric series:
Series 1: 1+12+14+18+116+\displaystyle 1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \dots
First term a1=1\displaystyle a_1 = 1, common ratio r1=12\displaystyle r_1 = \frac{1}{2}.
S1=111/2=2S_1 = \frac{1}{1 - 1/2} = 2

Series 2: 13+19+127+\displaystyle \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \dots
First term a2=13\displaystyle a_2 = \frac{1}{3}, common ratio r2=13\displaystyle r_2 = \frac{1}{3}.
S2=1/311/3=12S_2 = \frac{1/3}{1 - 1/3} = \frac{1}{2}

The total sum is:
Total Sum=S1+S2=2+12=52\text{Total Sum} = S_1 + S_2 = 2 + \frac{1}{2} = \frac{5}{2}
Hence, **Option D** (None of these) is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

Related Comparison Tables

More Questions from Sequence and Series

Ready to Master Sequence and Series?

Practice all 212 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free