Sequence and SeriesMCQMTP June 2023 Series IQuestion 1858 of 212
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The 5th\displaystyle 5^{th} and 8th\displaystyle 8^{th} terms of a GP series is 27\displaystyle 27 and 729\displaystyle 729. Then find the 10th\displaystyle 10^{th} term.

Options

A729\displaystyle 729
B243\displaystyle 243
C81683\displaystyle 81683
D6561\displaystyle 6561
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Correct Answer

Option d6561\displaystyle 6561

All Options:

  • A729\displaystyle 729
  • B243\displaystyle 243
  • C81683\displaystyle 81683
  • D6561\displaystyle 6561

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Detailed Solution & Explanation

Let the first term be a\displaystyle a and common ratio be r\displaystyle r.
Given:
t5=ar4=27t_5 = ar^4 = 27
t8=ar7=729t_8 = ar^7 = 729
Dividing:
r3=72927=27    r=3r^3 = \frac{729}{27} = 27 \implies r = 3

The 10th\displaystyle 10^{\text{th}} term is:
t10=t8r2=72932=7299=6561t_{10} = t_8 \cdot r^2 = 729 \cdot 3^2 = 729 \cdot 9 = 6561
Hence, **Option D** is the correct answer.

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

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