Sequence and SeriesMTP Dec 23Question 1861 of 142
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The 3rd\displaystyle 3^{rd} term of a G.P is 23\displaystyle \frac{2}{3} and 6th\displaystyle 6^{th} term is 281\displaystyle \frac{2}{81}, then the first term is

Options

A6\displaystyle 6
B1/3\displaystyle 1/3
C9\displaystyle 9
D2\displaystyle 2
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Correct Answer

✅ Option d — 2\displaystyle 2

All Options:

  • A6\displaystyle 6
  • B1/3\displaystyle 1/3
  • C9\displaystyle 9
  • D2\displaystyle 2

About This Chapter: Sequence and Series

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Arithmetic & Geometric Progressions

This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.

View Official ICAI Syllabus

Exam Strategy Tip

For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.

More Questions from Sequence and Series

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The sum of first three terms of a G.P. is 212\displaystyle \frac{21}{2} and their product is 27. Which of the following is not a term of the G.P., if the numbers are positive?

Insert 4 numbers between 2 and 22 such that the resulting sequence is an Arithmetic Progression (A.P.).

Find the sum of series 1+12+14+…\displaystyle 1 + \frac{1}{2} + \frac{1}{4} + \dots upto 6 terms.

If the sum of 'n\displaystyle n' terms of an AP (Arithmetic Progression) is 2n2\displaystyle 2n^2, the fifth term is ____.

The sum of first n\displaystyle n terms an AP is 3n2+5n\displaystyle 3n^2+5n. The series is:

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