Correct Answer
✅ Option c — $\frac{1}{81}(10^{n+1} - 9n - 10)$
All Options:
- A$\frac{1}{27}(10^{n+1} - 9n - 10)$
- B$\frac{1}{9}(10^{n+1} - 9n - 10)$
- C$\frac{1}{81}(10^{n+1} - 9n - 10)$
- DNone of these
About This Chapter: Sequence and Series
Paper
Paper 3: Quantitative Aptitude
Weightage
4-6 Marks
Key Topics
Arithmetic & Geometric Progressions
This chapter covers Arithmetic Progressions (AP) and Geometric Progressions (GP). Students learn how to find the nth term, sum of n terms, arithmetic/geometric means, and sum to infinity of a GP.
View Official ICAI SyllabusExam Strategy Tip
For complex 'sum of series' questions, a great hack is to substitute n = 1 and n = 2 into the question and the options to see which one matches, completely bypassing the formula.
More Questions from Sequence and Series
If the sum of '$n$' terms of an AP (Arithmetic Progression) is $2n^2$, the fifth term is ____.
The sum of first $n$ terms an AP is $3n^2+5n$. The series is:
If $2+6+10+14+.........+x=882$ then the value of $x$ is
If the sum of five terms of AP is $75$. Find the third term of the series.
The $20^{th}$ term of arithmetic progression whose $6^{th}$ term is $38$ and $10^{th}$ term is $66$ is:
Divide $69$ into $3$ parts which are in A.P. and are such that the product of first two parts is $483$.
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