The chance of getting a sum of 10 in a simple single throw is

Option c: 1/12. Solution: Sum = 10 with Two Dice Total outcomes = 36 Favorable outcomes (sum = 10): - (4, 6) : 4+6=10 ✓ - (5, 5) : 5+5=10 ✓ - (6, 4) : 6+4=10 ✓ Favorable = 3 P(sum=10) = 3/36 = 1/12 Hence, Option C is the correct answer.

The chance of getting a sum of $10$ in a simple single throw is

The correct answer is Option c: $\frac{1}{12}$. **Sum = 10 with Two Dice** Total outcomes = 36 Favorable outcomes (sum = 10): - $(4, 6)$: $4+6=10$ ✓ - $(5, 5)$: $5+5=10$ ✓ - $(6, 4)$: $6+4=10$ ✓ Favorable = **3** $$P(\text{sum}=10) = \frac{3}{36} = \frac{1}{12}$$ Hence, **Option C** is the correct answer.

ProbabilityMCQMTP Dec 2023 Series I / MTP Sep 24 IQuestion 3305 of 187

All Questions

The chance of getting a sum of $\displaystyle 10$ in a simple single throw is

Options

\displaystyle \frac{10}{36}

\displaystyle \frac{1}{2}

\displaystyle \frac{1}{12}

DNone of these

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Correct Answer

✅ Option c — $\displaystyle \frac{1}{12}$

All Options:

A $\displaystyle \frac{10}{36}$
B $\displaystyle \frac{1}{2}$
C $\displaystyle \frac{1}{12}$
DNone of these

Detailed Solution & Explanation

**Sum = 10 with Two Dice** Total outcomes = 36 Favorable outcomes (sum = 10): -

\displaystyle (4, 6)

\displaystyle 4+6=10

✓ -

\displaystyle (5, 5)

\displaystyle 5+5=10

✓ -

\displaystyle (6, 4)

\displaystyle 6+4=10

✓ Favorable = **3**

P(\text{sum}=10) = \frac{3}{36} = \frac{1}{12}

Hence, **Option C** is the correct answer.

About This Chapter: Probability

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Probability Operations, Expected Value

A logic-heavy chapter dealing with random experiments, events (mutually exclusive, exhaustive), set theory probability, conditional probability, and Bayes' Theorem. It forms the basis for Theoretical Distributions.

View Official ICAI Syllabus

Exam Strategy Tip

Always draw a quick Venn Diagram or tree when faced with 'At least one' or 'Only A but not B' wording. It saves you from double-counting.

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The chance of getting a sum of 10\displaystyle 1010 in a simple single throw is