Theoretical DistributionsPYQ Dec 23Question 3555 of 221
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If 'x' and 'y' are independent normal variate with mean and SD μ1,μ2\displaystyle \mu_1, \mu_2 and σ1,σ2\displaystyle \sigma_1, \sigma_2 respectively, then for z=x+y\displaystyle z = x + y which also follows normal distribution mean and SD are:

Options

AMean =μ1+μ2\displaystyle = \mu_1 + \mu_2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}
BMean =\displaystyle = (μ1+μ2)/2\displaystyle (\mu_1 + \mu_2) / 2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}
CMean =μ1μ2\displaystyle = \mu_1 - \mu_2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}
DMean =(μ1μ2)/2\displaystyle = (\mu_1 - \mu_2) / 2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}
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Correct Answer

Option aMean =μ1+μ2\displaystyle = \mu_1 + \mu_2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}

All Options:

  • AMean =μ1+μ2\displaystyle = \mu_1 + \mu_2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}
  • BMean =\displaystyle = (μ1+μ2)/2\displaystyle (\mu_1 + \mu_2) / 2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}
  • CMean =μ1μ2\displaystyle = \mu_1 - \mu_2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}
  • DMean =(μ1μ2)/2\displaystyle = (\mu_1 - \mu_2) / 2, SD =σ12+σ22\displaystyle = \sqrt{\sigma_1^2 + \sigma_2^2}

About This Chapter: Theoretical Distributions

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Binomial, Poisson, Normal Distribution

This chapter covers Binomial, Poisson, Normal Distribution and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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