Index NumbersMCQMTP Dec 23 Series IIQuestion 3928 of 197
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From the following dataGroup | A | B | C | D | E | FGroup Index | 120 | 132 | 98 | 115 | 108 | 95Weight | 6 | 3 | 4 | 2 | 1 | 4The general Index (I) is given by:

Options

A123.25\displaystyle 123.25
B217.15\displaystyle 217.15
C111.30\displaystyle 111.30
DNone of these
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Correct Answer

✅ Option c — 111.30\displaystyle 111.30

All Options:

  • A123.25\displaystyle 123.25
  • B217.15\displaystyle 217.15
  • C111.30\displaystyle 111.30
  • DNone of these

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Detailed Solution & Explanation

To calculate the General Index, we use the weighted arithmetic mean of the group indices: General Index=∑IW∑W\text{General Index} = \frac{\sum I W}{\sum W} Let's compute: - Group A: I=120,W=6  ⟹  IW=720\displaystyle I = 120, W = 6 \implies I W = 720 - Group B: I=132,W=3  ⟹  IW=396\displaystyle I = 132, W = 3 \implies I W = 396 - Group C: I=98,W=4  ⟹  IW=392\displaystyle I = 98, W = 4 \implies I W = 392 - Group D: I=115,W=2  ⟹  IW=230\displaystyle I = 115, W = 2 \implies I W = 230 - Group E: I=108,W=1  ⟹  IW=108\displaystyle I = 108, W = 1 \implies I W = 108 - Group F: I=95,W=4  ⟹  IW=380\displaystyle I = 95, W = 4 \implies I W = 380 1. **Sum of Weights (∑W\displaystyle \sum W)**: ∑W=6+3+4+2+1+4=20\sum W = 6 + 3 + 4 + 2 + 1 + 4 = 20 2. **Sum of Products (∑IW\displaystyle \sum I W)**: ∑IW=720+396+392+230+108+380=2226\sum I W = 720 + 396 + 392 + 230 + 108 + 380 = 2226 3. **Calculate General Index**: General Index=222620=111.30\text{General Index} = \frac{2226}{20} = 111.30 Hence, **Option C** is the correct answer.

About This Chapter: Index Numbers

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Construction of Index Numbers, Time Series

This chapter covers Construction of Index Numbers, Time Series and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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