Linear InequalitiesPYQ Sept 25Question 4107 of 73
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Which of the following is a solution of the inequality 5x3x65\displaystyle \frac{5x}{3} \le \frac{x}{6} - 5 ?

Options

A(,103]\displaystyle (-\infty, -\frac{10}{3}]
B(,103)\displaystyle (-\infty, -\frac{10}{3})
C(,83]\displaystyle (-\infty, -\frac{8}{3}]
D(,83)\displaystyle (-\infty, -\frac{8}{3})
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Correct Answer

Option a(,103]\displaystyle (-\infty, -\frac{10}{3}]

All Options:

  • A(,103]\displaystyle (-\infty, -\frac{10}{3}]
  • B(,103)\displaystyle (-\infty, -\frac{10}{3})
  • C(,83]\displaystyle (-\infty, -\frac{8}{3}]
  • D(,83)\displaystyle (-\infty, -\frac{8}{3})

Detailed Solution & Explanation

Given inequality: 5x3x65\frac{5x}{3} \le \frac{x}{6} - 5
To clear the fractions, multiply both sides by the least common multiple of the denominators (3 and 6), which is 6: 6(5x3)6(x65)6 \left( \frac{5x}{3} \right) \le 6 \left( \frac{x}{6} - 5 \right) 2(5x)x302(5x) \le x - 30 10xx3010x \le x - 30
Subtract x\displaystyle x from both sides: 9x309x \le -30
Divide both sides by 9: x309    x103x \le -\frac{30}{9} \implies x \le -\frac{10}{3}
In interval notation, the solution is: x(,103]x \in \left(-\infty, -\frac{10}{3}\right]
Hence, **Option A** is the correct answer.

About This Chapter: Linear Inequalities

Paper

Paper 3: Quantitative Aptitude

Weightage

1-3 Marks

Key Topics

Linear Inequalities in one & two variables

This chapter covers Linear Inequalities in one & two variables and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 1-3 Marks weightage. Focus on understanding core concepts rather than memorizing.

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