EquationsMCQMTP Jun 23 Series IQuestion 1035 of 221
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The ages of two persons are in the ratio 5:7\displaystyle 5:7. Eighteen years ago their ages were in the ratio of 8:13\displaystyle 8:13, their present ages (in years) are:

Options

A50, 70
B70, 50
C40, 56
DNone of these
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Correct Answer

Option a50, 70

All Options:

  • A50, 70
  • B70, 50
  • C40, 56
  • DNone of these

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Detailed Solution & Explanation

Let the present ages of the two persons be 5x\displaystyle 5x and 7x\displaystyle 7x.
Eighteen years ago, their ages were 5x18\displaystyle 5x - 18 and 7x18\displaystyle 7x - 18.
According to the question, the ratio of their ages 18 years ago was 8:13\displaystyle 8:13:
5x187x18=813\frac{5x - 18}{7x - 18} = \frac{8}{13}
Cross-multiplying:
13(5x18)=8(7x18)13(5x - 18) = 8(7x - 18)
65x234=56x14465x - 234 = 56x - 144
65x56x=23414465x - 56x = 234 - 144
9x=90    x=109x = 90 \implies x = 10
Thus, their present ages are:
5x=5(10)=50 years5x = 5(10) = 50 \text{ years}
7x=7(10)=70 years7x = 7(10) = 70 \text{ years}
**Option a**

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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