EquationsMCQPYQ Nov 19Question 986 of 221
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2x+510+3x+1015=5\displaystyle \frac{2x+5}{10} + \frac{3x+10}{15} = 5, find x\displaystyle x

Options

A10.58\displaystyle 10.58
B9.58\displaystyle 9.58
C9.5\displaystyle 9.5
DNone of these
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Correct Answer

Option b9.58\displaystyle 9.58

All Options:

  • A10.58\displaystyle 10.58
  • B9.58\displaystyle 9.58
  • C9.5\displaystyle 9.5
  • DNone of these

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Detailed Solution & Explanation

The given equation is:
2x+510+3x+1015=5\frac{2x+5}{10} + \frac{3x+10}{15} = 5
Taking the Least Common Multiple (LCM) of 10\displaystyle 10 and 15\displaystyle 15, which is 30\displaystyle 30, we can rewrite the equation as:
3(2x+5)+2(3x+10)30=5\frac{3(2x+5) + 2(3x+10)}{30} = 5
Multiplying both sides by 30\displaystyle 30:
3(2x+5)+2(3x+10)=1503(2x+5) + 2(3x+10) = 150
Expanding the terms:
6x+15+6x+20=1506x + 15 + 6x + 20 = 150
12x+35=15012x + 35 = 150
12x=1503512x = 150 - 35
12x=11512x = 115
x=115129.58x = \frac{115}{12} \approx 9.58
Hence, **Option B** is the correct answer.

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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