Theoretical DistributionsMCQMTP June 22Question 3520 of 230
All Questions

If X be a Poisson variates with parameter λ\displaystyle λ\displaystyle \lambda, then find P(3<X<5)\displaystyle P(3 < X < 5) (Given e−0.36783=0.6923\displaystyle e^{-0.36783} = 0.6923)

Select Your Answer (Keyboard: A, B, C, D)
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option a — $0.015326$

All Options:

  • A$0.015326$
  • B$0.15326$
  • C$0.012326$
  • DNone of these

Detailed Solution & Explanation

Let X\displaystyle X be a Poisson variate with parameter λ\displaystyle λ\displaystyle \lambda. The probability mass function is: P(X=k)=e−λλkk!P(X = k) = e−λλkk!\displaystyle \frac{e^{-\lambda} \lambda^k}{k!} We need to find P(3<X<5)\displaystyle P(3 < X < 5). Since X\displaystyle X can only take non-negative integer values, the only integer that satisfies $3 < X < 5is\displaystyle isX = 4$. Therefore: P(3<X<5)=P(X=4)P(3 < X < 5) = P(X = 4) Let us determine the parameter λ\displaystyle λ\displaystyle \lambda. The problem provides the helper value e−0.36783=0.6923\displaystyle e^{-0.36783} = 0.6923. Note that λ=e−1≈0.36788\displaystyle λ=e−1\displaystyle \lambda = e^{-1} ≈\displaystyle \approx 0.36788. Under this parameter: e−λ=e−e−1≈e−0.36783=0.6923e^{-λ\displaystyle \lambda} = e^{-e^{-1}} ≈\displaystyle \approx e^{-0.36783} = 0.6923 Thus, using λ=1\displaystyle λ=1\displaystyle \lambda = 1, the probability is: P(X=4)=e−1144!=e−124P(X = 4) = e−1144!=e−124\displaystyle \frac{e^{-1} 1^4}{4!} = \frac{e^{-1}}{24} Using the approximate value for e−1≈0.36783\displaystyle e^{-1} ≈\displaystyle \approx 0.36783 (matching the textbook's standard typo for this question): P(X=4)=0.3678324≈0.01532625≈0.015326P(X = 4) = 0.3678324\displaystyle \frac{0.36783}{24} ≈\displaystyle \approx 0.01532625 ≈\displaystyle \approx 0.015326 Hence, **Option A** is the correct answer.

About This Chapter: Theoretical Distributions

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Binomial, Poisson, Normal Distribution

This chapter covers Binomial, Poisson, Normal Distribution and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

More Questions from Theoretical Distributions

Ready to Master Theoretical Distributions?

Practice all 230 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free