The common region represented by the following in equalities $\displaystyle L_1: x + y \le 4; L_2: 2x + y \ge 2$ is

The linear relationship between two variables in an inequality:

On solving the inequalities $\displaystyle 5x + y \le 100$, $\displaystyle x + y \le 60$, $\displaystyle x \ge 0$, $\displaystyle y \ge 0$, we get the following solution:

On solving the inequalities; we get $\displaystyle 6x + y \ge 18$, $\displaystyle x + 4y \ge 12$, $\displaystyle 2x + y \ge 10$

Solve for $\displaystyle x$ of the inequalities $\displaystyle 2 \le \frac{3x - 2}{5} \le 4$ where $\displaystyle x \in N$

The common region in the graph of the inequalities $\displaystyle x + y \le 4$, $\displaystyle x - y \le 4$, $\displaystyle x \ge 2$ is

XYZ Company has a policy for its recruitment as it should not recruit more than eight men $\displaystyle (x)$ to three women $\displaystyle (y)$. How can this fact be expressed in inequality?