A company produces two products A and B, each of which requires processing in two machines. The first machine can be used for most for $60$ hours, the second machine can be used for most for $40$ hours. The product A requires $2$ hours on machine one and one hour on machine two. The product B requires one hour on machine one and two hours on machine two. Express above situation using linear inequalities

The linear relationship between two variables in an inequality:

On solving the inequalities $5x + y \le 100$, $x + y \le 60$, $x \ge 0$, $y \ge 0$, we get the following solution:

On solving the inequalities; we get $6x + y \ge 18$, $x + 4y \ge 12$, $2x + y \ge 10$

Solve for $x$ of the inequalities $2 \le \frac{3x - 2}{5} \le 4$ where $x \in N$

The common region in the graph of the inequalities $x + y \le 4$, $x - y \le 4$, $x \ge 2$ is

XYZ Company has a policy for its recruitment as it should not recruit more than eight men $(x)$ to three women $(y)$. How can this fact be expressed in inequality?