Mathematics for FinancePYQ Jun 23Question 1243 of 512
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Mr. Ram invested a total of 1,00,000\displaystyle 1,00,000 in two different banks for a fixed period. The first bank yields an interest of 9%\displaystyle 9\% p.a. and second, 11%\displaystyle 11\% per annum. If the total interest at the end of one year is 9.75%\displaystyle 9.75\% p.a., there the amount invested in these banks are respectively:

Options

A52,500,47,500\displaystyle 52,500, 47,500
B62,500,37,500\displaystyle 62,500, 37,500
C57,500,42,500\displaystyle 57,500, 42,500
D67,500,32,500\displaystyle 67,500, 32,500
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Correct Answer

✅ Option b — 62,500,37,500\displaystyle 62,500, 37,500

All Options:

  • A52,500,47,500\displaystyle 52,500, 47,500
  • B62,500,37,500\displaystyle 62,500, 37,500
  • C57,500,42,500\displaystyle 57,500, 42,500
  • D67,500,32,500\displaystyle 67,500, 32,500

Detailed Solution & Explanation

**Derivation of Invested Sums in Two Banks** Given: - Total investment = Rs. 1,00,000\displaystyle \text{Rs. }1,00,000 - Bank 1 rate (r1\displaystyle r_1) = 9%\displaystyle 9\% simple interest - Bank 2 rate (r2\displaystyle r_2) = 11%\displaystyle 11\% simple interest - Weighted average rate earned = 9.75%\displaystyle 9.75\% simple interest **Step 1: Use the allegation rule to find the ratio of investments** Ratio P1P2=r2−ravgravg−r1\text{Ratio } \frac{P_1}{P_2} = \frac{r_2 - r_{\text{avg}}}{r_{\text{avg}} - r_1} P1P2=11−9.759.75−9=1.250.75=53\frac{P_1}{P_2} = \frac{11 - 9.75}{9.75 - 9} = \frac{1.25}{0.75} = \frac{5}{3} **Step 2: Divide the total investment in the ratio 5:3** - Amount in Bank 1 (P1\displaystyle P_1) = 100000×58=Rs. 62,500\displaystyle 100000 \times \frac{5}{8} = \text{Rs. }62,500 - Amount in Bank 2 (P2\displaystyle P_2) = 100000×38=Rs. 37,500\displaystyle 100000 \times \frac{3}{8} = \text{Rs. }37,500 Hence, **Option B** is the correct answer.

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