Mathematics of FinanceMCQMTP Oct 21, ICAI SMQuestion 1337 of 512
All Questions

A sum of money amount to 6,200\displaystyle 6,200 in 2\displaystyle 2 years and 7,400\displaystyle 7,400 in 3\displaystyle 3 years. The principal and rate

Options

A3,800,31.57%\displaystyle 3,800, 31.57\%
B3,000,20%\displaystyle 3,000, 20\%
C3,500,15%\displaystyle 3,500, 15\%
Dnone of these
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Correct Answer

Option a3,800,31.57%\displaystyle 3,800, 31.57\%

All Options:

  • A3,800,31.57%\displaystyle 3,800, 31.57\%
  • B3,000,20%\displaystyle 3,000, 20\%
  • C3,500,15%\displaystyle 3,500, 15\%
  • Dnone of these

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Detailed Solution & Explanation

**Derivation of Principal and Rate of Simple Interest** Given: - Amount in 2\displaystyle 2 years (A2\displaystyle A_2) = Rs. 6,200\displaystyle \text{Rs. }6,200 - Amount in 3\displaystyle 3 years (A3\displaystyle A_3) = Rs. 7,400\displaystyle \text{Rs. }7,400 **Step 1: Find Simple Interest for 1 year (SI1\displaystyle SI_1)** SI1=A3A2=74006200=Rs. 1,200SI_1 = A_3 - A_2 = 7400 - 6200 = \text{Rs. }1,200 **Step 2: Find the Principal (P\displaystyle P)** P=A2(2×SI1)=6200(2×1200)=62002400=Rs. 3,800P = A_2 - (2 \times SI_1) = 6200 - (2 \times 1200) = 6200 - 2400 = \text{Rs. }3,800 **Step 3: Calculate the Rate of Interest (R\displaystyle R)** SI1=P×R×1100SI_1 = \frac{P \times R \times 1}{100} 1200=3800×R×11001200 = \frac{3800 \times R \times 1}{100} 1200=38R1200 = 38 R R=12003831.578% per annumR = \frac{1200}{38} \approx 31.578\% \text{ per annum} Hence, **Option A** is the correct answer.

About This Chapter: Mathematics of Finance

Paper

Paper 3: Quantitative Aptitude

Weightage

12-16 Marks

Key Topics

Simple & Compound Interest, Annuity, Perpetuity

The most important mathematical chapter in the entire syllabus. It covers Simple Interest (SI), Compound Interest (CI), Nominal vs Effective rates, Present and Future Value, Annuities (Ordinary and Due), Sinking Funds, and Perpetuities. The concepts learned here are applied heavily in CA Intermediate and Final.

View Official ICAI Syllabus

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