Correct Answer
✅ Option c — 144
All Options:
- A24
- B164
- C144
- D336
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Detailed Solution & Explanation
Let us denote the positions in the row as .
Since the number of boys () is greater than the number of girls (), the only way to arrange them alternatively is to place the boys in the odd-numbered positions and the girls in the even-numbered positions:
Here:
- Boys occupy positions: (4 positions).
- Girls occupy positions: (3 positions).
Now, we arrange the individuals:
- The 4 distinct boys can be arranged in the 4 designated boy-positions in ways:
- The 3 distinct girls can be arranged in the 3 designated girl-positions in ways:
By the fundamental multiplication principle of counting, the total number of alternate arrangements is:
Hence, **Option C** is the correct answer.
About This Chapter: Permutations and Combinations
Paper
Paper 3: Quantitative Aptitude
Weightage
4-6 Marks
Key Topics
Factorials, Permutations, Combinations
This chapter deals with the fundamental principles of counting. It covers factorials, circular permutations, restricted permutations, combinations, and the differences between selecting items versus arranging them.
View Official ICAI SyllabusExam Strategy Tip
The most common mistake is confusing 'P' (Arrangement) with 'C' (Selection). If order matters (like opening a lock), use P. If order doesn't matter (like choosing a team), use C.
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More Questions from Permutations and Combinations
The value of in is
A person can go from place 'A' to 'B' by 11 different modes of transport but is allowed to return to 'A' by any mode other than the one earlier. The number of different ways in which the entire journey can be completed is:
If a man travels from place A to B in 10 ways then by how many ways can he come back by another train?
If find 'n'.
Which of the following is a correct statement.
. Find .
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