Correct Answer
✅ Option c — 4050
All Options:
- A650
- B580
- C4050
- D4060
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Detailed Solution & Explanation
If all points were non-collinear, the total number of ways to choose points would be:
However, we are given that of these points are collinear (they lie on the same straight line). Selecting any points from these collinear points will lie on a straight line and cannot form a triangle. The number of such invalid selections is:
Subtracting the invalid combinations from the total combinations gives the number of valid triangles:
Hence, **Option C** is the correct answer.
About This Chapter: Permutations and Combinations
Paper
Paper 3: Quantitative Aptitude
Weightage
4-6 Marks
Key Topics
Factorials, Permutations, Combinations
This chapter deals with the fundamental principles of counting. It covers factorials, circular permutations, restricted permutations, combinations, and the differences between selecting items versus arranging them.
View Official ICAI SyllabusExam Strategy Tip
The most common mistake is confusing 'P' (Arrangement) with 'C' (Selection). If order matters (like opening a lock), use P. If order doesn't matter (like choosing a team), use C.
Related Comparison Tables
More Questions from Permutations and Combinations
The value of in is
A person can go from place 'A' to 'B' by 11 different modes of transport but is allowed to return to 'A' by any mode other than the one earlier. The number of different ways in which the entire journey can be completed is:
If a man travels from place A to B in 10 ways then by how many ways can he come back by another train?
If find 'n'.
Which of the following is a correct statement.
. Find .
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