Number Series, Coding, Odd Man OutMTP May 20Question 2047 of 217
All Questions

Find missing term 7,26,63,124,215,342,?\displaystyle 7, 26, 63, 124, 215, 342, ?

Options

A391\displaystyle 391
B421\displaystyle 421
C481\displaystyle 481
D511\displaystyle 511
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option d — 511\displaystyle 511

All Options:

  • A391\displaystyle 391
  • B421\displaystyle 421
  • C481\displaystyle 481
  • D511\displaystyle 511

Detailed Solution & Explanation

We are given the series: 7,26,63,124,215,342,…\displaystyle 7, 26, 63, 124, 215, 342, \dots
Let's analyze each term in relation to perfect cubes:
- 7=23−1\displaystyle 7 = 2^3 - 1
- 26=33−1\displaystyle 26 = 3^3 - 1
- 63=43−1\displaystyle 63 = 4^3 - 1
- 124=53−1\displaystyle 124 = 5^3 - 1
- 215=63−1\displaystyle 215 = 6^3 - 1
- 342=73−1\displaystyle 342 = 7^3 - 1
The terms are of the form n3−1\displaystyle n^3 - 1 for consecutive natural numbers starting from 2\displaystyle 2.
The next term in the series must be 83−1\displaystyle 8^3 - 1:
83−1=512−1=5118^3 - 1 = 512 - 1 = 511
Hence, **Option D** is the correct answer.

More Questions from Number Series, Coding, Odd Man Out

Ready to Master Number Series, Coding, Odd Man Out?

Practice all 217 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free