Find the odd man out: 34, 105, 424, 2125, 12755.

Option a: 12755. Solution: Let's establish the mathematical pattern linking consecutive terms starting with T1 = 34: - T2 = T1 x 3 + 3 = 34 x 3 + 3 = 102 + 3 = 105 - T3 = T2 x 4 + 4 = 105 x 4 + 4 = 420 + 4 = 424 - T4 = T3 x 5 + 5 = 424 x 5 + 5 = 2120 + 5 = 2125 - T5 = T4 x 6 + 6 = 2125 x 6 + 6 = 12750 + 6 = 12756 (the series lists 12755, which is incorrect) This pattern (Tn = T{n-1} x (n+1) + (n+1)) is perfectly consistent for all terms except 12755, which should be 12756. Therefore, 12755 is the odd man out. Hence, Option A is the correct answer.

Find the odd man out: $34, 105, 424, 2125, 12755$.

The correct answer is Option a: $12755$. Let's establish the mathematical pattern linking consecutive terms starting with $T_1 = 34$: - $T_2 = T_1 \times 3 + 3 = 34 \times 3 + 3 = 102 + 3 = 105$ - $T_3 = T_2 \times 4 + 4 = 105 \times 4 + 4 = 420 + 4 = 424$ - $T_4 = T_3 \times 5 + 5 = 424 \times 5 + 5 = 2120 + 5 = 2125$ - $T_5 = T_4 \times 6 + 6 = 2125 \times 6 + 6 = 12750 + 6 = 12756$ (the series lists $12755$, which is incorrect) This pattern ($T_n = T_{n-1} \times (n+1) + (n+1)$) is perfectly consistent for all terms except $12755$, which should be $12756$. Therefore, $12755$ is the odd man out. Hence, **Option A** is the correct answer.

Number Series, Coding, Odd Man OutMTP June 2023 Series IQuestion 2192 of 217

All Questions

Find the odd man out: $\displaystyle 34, 105, 424, 2125, 12755$ .

Options

\displaystyle 12755

\displaystyle 2125

\displaystyle 424

\displaystyle 34

For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option a — $\displaystyle 12755$

All Options:

A $\displaystyle 12755$
B $\displaystyle 2125$
C $\displaystyle 424$
D $\displaystyle 34$

Detailed Solution & Explanation

Let's establish the mathematical pattern linking consecutive terms starting with

\displaystyle T_1 = 34

:
-

\displaystyle T_2 = T_1 \times 3 + 3 = 34 \times 3 + 3 = 102 + 3 = 105

\displaystyle T_3 = T_2 \times 4 + 4 = 105 \times 4 + 4 = 420 + 4 = 424

\displaystyle T_4 = T_3 \times 5 + 5 = 424 \times 5 + 5 = 2120 + 5 = 2125

\displaystyle T_5 = T_4 \times 6 + 6 = 2125 \times 6 + 6 = 12750 + 6 = 12756

(the series lists

\displaystyle 12755

, which is incorrect)

This pattern (

\displaystyle T_n = T_{n-1} \times (n+1) + (n+1)

) is perfectly consistent for all terms except

\displaystyle 12755

, which should be

\displaystyle 12756

. Therefore,

\displaystyle 12755

is the odd man out.

Hence, **Option A** is the correct answer.

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Find the odd man out: 34,105,424,2125,12755\displaystyle 34, 105, 424, 2125, 1275534,105,424,2125,12755.