Direction TestPYQ July 21Question 2288 of 165
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A and B start moving towards each other from two places 200m apart. After walking 60m, B turns left and goes 20m, then he turns right and goes 40m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between them now?

Options

A80 m
B70 m
C40 m
D60 m
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Correct Answer

✅ Option c — 40 m

All Options:

  • A80 m
  • B70 m
  • C40 m
  • D60 m

Detailed Solution & Explanation

Let the road lie along the X-axis from X=0\displaystyle X = 0 to X=200\displaystyle X = 200.
A and B walk at the same speed, meaning their total distance walked is identical.
Let us trace B's movement starting at X=200\displaystyle X = 200 moving West towards X=0\displaystyle X = 0:
- Walks 60 m West: reaches X=140\displaystyle X = 140 on the road.
- Turns left (South) and walks 20 m: reaches (140,−20)\displaystyle (140, -20).
- Turns right (West) and walks 40 m: reaches (100,−20)\displaystyle (100, -20).
- Turns right (North) and returns 20 m back to the road: reaches (100,0)\displaystyle (100, 0).
Total distance B walked is 60+20+40+20=140\displaystyle 60 + 20 + 40 + 20 = 140 m.
Since A walks with the same speed, A walks a total of 140\displaystyle 140 m along the road starting from X=0\displaystyle X = 0 towards X=200\displaystyle X = 200:
- A reaches (140,0)\displaystyle (140, 0).
The current distance between A and B is:
Distance=140−100=40 m\text{Distance} = 140 - 100 = 40\text{ m}
Hence, **Option C** is the correct answer.

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