Direction TestMTP June 24 Series IQuestion 2326 of 165
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A child is looking for his father. He went 90\displaystyle 90 meters in the east before turning to his right. He went 20\displaystyle 20 meters before turning to his right again to look for his father at his uncle's place 30\displaystyle 30 meters from this point. His father was not there. From there, he went 100\displaystyle 100 meters to his north before meeting his father in a street. How far did the son meet his father from starting point ?

Options

A80\displaystyle 80 m
B90\displaystyle 90 m
C100\displaystyle 100 m
D110\displaystyle 110 m
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Correct Answer

✅ Option c — 100\displaystyle 100 m

All Options:

  • A80\displaystyle 80 m
  • B90\displaystyle 90 m
  • C100\displaystyle 100 m
  • D110\displaystyle 110 m

Detailed Solution & Explanation

Let starting point be (0,0)\displaystyle (0,0).
- Walks 90 m East   ⟹  (90,0)\displaystyle \implies (90, 0).
- Turns right (South) and walks 20 m   ⟹  (90,−20)\displaystyle \implies (90, -20).
- Turns right (West) and walks 30 m   ⟹  (60,−20)\displaystyle \implies (60, -20).
- Walks 100 m North   ⟹  (60,80)\displaystyle \implies (60, 80).
The distance from starting point (0,0)\displaystyle (0,0) to the final position (60,80)\displaystyle (60, 80) is:
Distance=602+802=3600+6400=10000=100 m\text{Distance} = \sqrt{60^2 + 80^2} = \sqrt{3600 + 6400} = \sqrt{10000} = 100\text{ m}
Hence, **Option C** is the correct answer.

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