For the non-overlapping classes 0-19 , 20-39 , 40-59 the class mark of the class 0-19 is

Option c: 9.5. Solution: For any class interval in a frequency distribution, the class mark (also known as the mid-point or mid-value) is calculated as the arithmetic average of the lower and upper limits of that class: Class Mark = Class Limit + Upper Class Limit2 For the first class interval, 0-19 : - The Lower Class Limit is 0 . - The Upper Class Limit is 19 . Applying the formula: Class Mark = 0 + 19/2 = 19/2 = 9.5 Even if we convert the inclusive classes to exclusive class boundaries (which would be -0.5 to 19.5 ), the class mark remains the same: Class Mark = -0.5 + 19.5/2 = 19/2 = 9.5 This matches Option C. Hence, Option C is the correct answer.

For the non-overlapping classes $0-19$, $20-39$, $40-59$ the class mark of the class $0-19$ is

The correct answer is Option c: $9.5$. For any class interval in a frequency distribution, the **class mark** (also known as the mid-point or mid-value) is calculated as the arithmetic average of the lower and upper limits of that class: $$\text{Class Mark} = \frac{\text{Lower Class Limit} + \text{Upper Class Limit}}{2}$$ For the first class interval, $0-19$: - The Lower Class Limit is $0$. - The Upper Class Limit is $19$. Applying the formula: $$\text{Class Mark} = \frac{0 + 19}{2} = \frac{19}{2} = 9.5$$ Even if we convert the inclusive classes to exclusive class boundaries (which would be $-0.5$ to $19.5$), the class mark remains the same: $$\text{Class Mark} = \frac{-0.5 + 19.5}{2} = \frac{19}{2} = 9.5$$ This matches Option C. Hence, **Option C** is the correct answer.

Statistical Representation of DataMCQMTP March 22Question 2739 of 295

All Questions

For the non-overlapping classes $\displaystyle 0-19$ , $\displaystyle 20-39$ , $\displaystyle 40-59$ the class mark of the class $\displaystyle 0-19$ is

Options

\displaystyle 0

\displaystyle 19

\displaystyle 9.5

DNone of these

For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option c — $\displaystyle 9.5$

All Options:

A $\displaystyle 0$
B $\displaystyle 19$
C $\displaystyle 9.5$
DNone of these

Detailed Solution & Explanation

For any class interval in a frequency distribution, the **class mark** (also known as the mid-point or mid-value) is calculated as the arithmetic average of the lower and upper limits of that class:

\text{Class Mark} = \frac{\text{Lower Class Limit} + \text{Upper Class Limit}}{2}

For the first class interval,

\displaystyle 0-19

: - The Lower Class Limit is

\displaystyle 0

. - The Upper Class Limit is

\displaystyle 19

. Applying the formula:

\text{Class Mark} = \frac{0 + 19}{2} = \frac{19}{2} = 9.5

Even if we convert the inclusive classes to exclusive class boundaries (which would be

\displaystyle -0.5

\displaystyle 19.5

), the class mark remains the same:

\text{Class Mark} = \frac{-0.5 + 19.5}{2} = \frac{19}{2} = 9.5

This matches Option C. Hence, **Option C** is the correct answer.

About This Chapter: Statistical Representation of Data

Paper

Paper 3: Quantitative Aptitude

Weightage

2-4 Marks

Key Topics

Data, Frequency Distribution, Graphical Representation

This chapter covers Data, Frequency Distribution, Graphical Representation and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 2-4 Marks weightage. Focus on understanding core concepts rather than memorizing.

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For the non-overlapping classes 0−19\displaystyle 0-190−19, 20−39\displaystyle 20-3920−39, 40−59\displaystyle 40-5940−59 the class mark of the class 0−19\displaystyle 0-190−19 is