Statistical Description of DataMTP June 24 Series IIQuestion 2758 of 295
All Questions

If the width of each of ten classes in a frequency distribution is 2.5\displaystyle 2.5 and the lower class boundary is 5.1\displaystyle 5.1, then the upper class boundary of the highest class is

Options

A30.1\displaystyle 30.1
B31.1\displaystyle 31.1
C30\displaystyle 30
D27.6\displaystyle 27.6
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Correct Answer

✅ Option a — 30.1\displaystyle 30.1

All Options:

  • A30.1\displaystyle 30.1
  • B31.1\displaystyle 31.1
  • C30\displaystyle 30
  • D27.6\displaystyle 27.6

Detailed Solution & Explanation

We are given the following parameters of a grouped frequency distribution: - Total number of classes, n=10\displaystyle n = 10 - Width (or size) of each class, w=2.5\displaystyle w = 2.5 - Lower class boundary of the lowest (first) class, LCB1=5.1\displaystyle LCB_1 = 5.1 Since the classes are contiguous, the total width spanned by all 10\displaystyle 10 classes is the product of the number of classes and the class width: Total Width=n×w=10×2.5=25.0\text{Total Width} = n \times w = 10 \times 2.5 = 25.0 The upper class boundary of the highest (10th) class (UCB10\displaystyle UCB_{10}) will be the lower class boundary of the first class plus this total spanned width: UCB10=LCB1+Total Width=5.1+25.0=30.1UCB_{10} = LCB_1 + \text{Total Width} = 5.1 + 25.0 = 30.1 This matches Option A. Hence, **Option A** is the correct answer.

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