Statistical Description of DataMTP June 24 Series IIQuestion 2759 of 295
All Questions

Let L\displaystyle L be the lower class boundary of a class in a frequency distribution and m\displaystyle m be the mid point of the class. Which one of the following is the higher class boundary of the class?

Options

Am+2\displaystyle m+2
BL+m+L\displaystyle L+m+L
C2m−L\displaystyle 2m-L
Dm−2L\displaystyle m-2L
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Correct Answer

✅ Option c — 2m−L\displaystyle 2m-L

All Options:

  • Am+2\displaystyle m+2
  • BL+m+L\displaystyle L+m+L
  • C2m−L\displaystyle 2m-L
  • Dm−2L\displaystyle m-2L

Detailed Solution & Explanation

Let U\displaystyle U represent the upper (higher) class boundary of the class interval. - The midpoint (or class mark) m\displaystyle m of a class interval is defined as the arithmetic mean of its lower class boundary L\displaystyle L and its upper class boundary U\displaystyle U: m=L+U2m = \frac{L + U}{2} To find the expression for the upper class boundary U\displaystyle U in terms of m\displaystyle m and L\displaystyle L, we solve the equation for U\displaystyle U: 1. Multiply both sides by 2\displaystyle 2: 2m=L+U2m = L + U 2. Subtract L\displaystyle L from both sides: U=2m−LU = 2m - L Thus, the higher class boundary is 2m−L\displaystyle 2m - L, which corresponds to Option C. Hence, **Option C** is the correct answer.

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