Let L be the lower class boundary of a class in a frequency distribution and m be the midpoint of the class. Which one of the following is the higher class boundary of the class?

Option c: 2m - L. Solution: Let L be the lower class boundary of a class and U be the upper class boundary. The midpoint of the class is given by the formula: m = L + U/2 To find the higher (upper) class boundary U in terms of m and L , we can rearrange the equation: 2m = L + U U = 2m - L Comparing this with the given options, we find it corresponds to Option C. Hence, Option C is the correct answer.

Let $L$ be the lower class boundary of a class in a frequency distribution and $m$ be the midpoint of the class. Which one of the following is the higher class boundary of the class?

The correct answer is Option c: $2m - L$. Let $L$ be the lower class boundary of a class and $U$ be the upper class boundary. The midpoint of the class is given by the formula: $$m = \frac{L + U}{2}$$ To find the higher (upper) class boundary $U$ in terms of $m$ and $L$, we can rearrange the equation: $$2m = L + U$$ $$U = 2m - L$$ Comparing this with the given options, we find it corresponds to Option C. Hence, **Option C** is the correct answer.

Statistical Representation of DataMCQMTP Nov 19Question 2774 of 295

All Questions

Let $\displaystyle L$ be the lower class boundary of a class in a frequency distribution and $\displaystyle m$ be the midpoint of the class. Which one of the following is the higher class boundary of the class?

Options

\displaystyle m + \frac{m+L}{2}

\displaystyle m + L

\displaystyle 2m - L

\displaystyle m - 2L

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Correct Answer

✅ Option c — $\displaystyle 2m - L$

All Options:

A $\displaystyle m + \frac{m+L}{2}$
B $\displaystyle m + L$
C $\displaystyle 2m - L$
D $\displaystyle m - 2L$

Detailed Solution & Explanation

Let

\displaystyle L

be the lower class boundary of a class and

\displaystyle U

be the upper class boundary. The midpoint of the class is given by the formula:

m = \frac{L + U}{2}

To find the higher (upper) class boundary

\displaystyle U

in terms of

\displaystyle m

and

\displaystyle L

, we can rearrange the equation:

2m = L + U

U = 2m - L

Comparing this with the given options, we find it corresponds to Option C. Hence, **Option C** is the correct answer.

About This Chapter: Statistical Representation of Data

Paper

Paper 3: Quantitative Aptitude

Weightage

2-4 Marks

Key Topics

Data, Frequency Distribution, Graphical Representation

This chapter covers Data, Frequency Distribution, Graphical Representation and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 2-4 Marks weightage. Focus on understanding core concepts rather than memorizing.

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Let L\displaystyle LL be the lower class boundary of a class in a frequency distribution and m\displaystyle mm be the midpoint of the class. Which one of the following is the higher class boundary of the class?