Statistical Description of DataMTP Nov 19Question 2774 of 295
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Let L\displaystyle L be the lower class boundary of a class in a frequency distribution and m\displaystyle m be the midpoint of the class. Which one of the following is the higher class boundary of the class?

Options

Am+m+L2\displaystyle m + \frac{m+L}{2}
Bm+L\displaystyle m + L
C2m−L\displaystyle 2m - L
Dm−2L\displaystyle m - 2L
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Correct Answer

✅ Option c — 2m−L\displaystyle 2m - L

All Options:

  • Am+m+L2\displaystyle m + \frac{m+L}{2}
  • Bm+L\displaystyle m + L
  • C2m−L\displaystyle 2m - L
  • Dm−2L\displaystyle m - 2L

Detailed Solution & Explanation

Let L\displaystyle L be the lower class boundary of a class and U\displaystyle U be the upper class boundary. The midpoint of the class is given by the formula: m=L+U2m = \frac{L + U}{2} To find the higher (upper) class boundary U\displaystyle U in terms of m\displaystyle m and L\displaystyle L, we can rearrange the equation: 2m=L+U2m = L + U U=2m−LU = 2m - L Comparing this with the given options, we find it corresponds to Option C. Hence, **Option C** is the correct answer.

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