Central Tendency & DispersionPYQ Dec 23Question 2875 of 473
All Questions

If mean of 5 observations x+1,x+3,x+5,x+7\displaystyle x+1, x+3, x+5, x+7 and x+9\displaystyle x+9 is given 15, then the value of x\displaystyle x will be:

Options

A10\displaystyle 10
B12\displaystyle 12
C8\displaystyle 8
D11\displaystyle 11
For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option a — 10\displaystyle 10

All Options:

  • A10\displaystyle 10
  • B12\displaystyle 12
  • C8\displaystyle 8
  • D11\displaystyle 11

Detailed Solution & Explanation

**Step 1: Compute the mean of the 5 observations.** Mean=(x+1)+(x+3)+(x+5)+(x+7)+(x+9)5\text{Mean} = \frac{(x+1)+(x+3)+(x+5)+(x+7)+(x+9)}{5} =5x+(1+3+5+7+9)5=5x+255=x+5= \frac{5x + (1+3+5+7+9)}{5} = \frac{5x + 25}{5} = x + 5 **Step 2: Set equal to 15 and solve.** x+5=15  ⟹  x=10x + 5 = 15 \implies x = 10 Hence, **Option A** is the correct answer.

More Questions from Central Tendency & Dispersion

Ready to Master Central Tendency & Dispersion?

Practice all 473 questions with instant feedback, earn XP, track your streaks, and ace your CA Foundation exam.

Start Practicing — It's Free