If the range of 28, 22, 40, 20, 15, 50 is

Option c: 35. Solution: We are given the dataset: 28, 22, 40, 20, 15, 50. - Maximum value (L) = 50 - Minimum value (S) = 15 The range is defined as the difference between the maximum and minimum values: text{Range} = L - S = 50 - 15 = 35 Hence, Option C is the correct answer.

If the range of $28, 22, 40, 20, 15, 50$ is

The correct answer is Option c: 35. We are given the dataset: $28, 22, 40, 20, 15, 50$. - Maximum value ($L$) = $50$ - Minimum value ($S$) = $15$ The range is defined as the difference between the maximum and minimum values: $$\text{Range} = L - S = 50 - 15 = 35$$ Hence, **Option C** is the correct answer.

Central Tendency & DispersionMTP Nov 20Question 3086 of 473

All Questions

If the range of $\displaystyle 28, 22, 40, 20, 15, 50$ is

Options

A40

B22

C35

DNone of these

For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option c — 35

All Options:

A40
B22
C35
DNone of these

Detailed Solution & Explanation

We are given the dataset:

\displaystyle 28, 22, 40, 20, 15, 50

. - Maximum value (

\displaystyle L

) =

\displaystyle 50

- Minimum value (

\displaystyle S

) =

\displaystyle 15

The range is defined as the difference between the maximum and minimum values:

\text{Range} = L - S = 50 - 15 = 35

Hence, **Option C** is the correct answer.

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If the range of 28,22,40,20,15,50\displaystyle 28, 22, 40, 20, 15, 5028,22,40,20,15,50 is