Central Tendency & DispersionPYQ Nov. 19Question 2954 of 473
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Find the median of the following. Class: 0-10, 10-20, 20-30, 30-40, 40-50; Freq: 2, 3, 4, 5, 6

Options

A35
B32
C36
D37.5
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Correct Answer

✅ Option b — 32

All Options:

  • A35
  • B32
  • C36
  • D37.5

Detailed Solution & Explanation

We are given the grouped frequency distribution: - Class Interval: 0−10,10−20,20−30,30−40,40−50\displaystyle 0-10, 10-20, 20-30, 30-40, 40-50 - Frequency (f\displaystyle f): 2,3,4,5,6\displaystyle 2, 3, 4, 5, 6 1. Compute cumulative frequencies (cf\displaystyle cf): - 0−10\displaystyle 0-10: cf=2\displaystyle cf = 2 - 10−20\displaystyle 10-20: cf=2+3=5\displaystyle cf = 2 + 3 = 5 - 20−30\displaystyle 20-30: cf=5+4=9\displaystyle cf = 5 + 4 = 9 - 30−40\displaystyle 30-40: cf=9+5=14\displaystyle cf = 9 + 5 = 14 - 40−50\displaystyle 40-50: cf=14+6=20\displaystyle cf = 14 + 6 = 20 2. Total frequency N=20\displaystyle N = 20, so N2=10\displaystyle \frac{N}{2} = 10. 3. The cumulative frequency just greater than 10\displaystyle 10 is 14\displaystyle 14, which corresponds to the median class 30−40\displaystyle 30-40. Thus: - Lower limit of median class: L=30\displaystyle L = 30 - Cumulative frequency of preceding class: cf=9\displaystyle cf = 9 - Frequency of median class: f=5\displaystyle f = 5 - Class interval width: i=10\displaystyle i = 10 4. Applying the median formula: Median=L+N2−cff×i=30+10−95×10=30+15×10=32\text{Median} = L + \frac{\frac{N}{2} - cf}{f} \times i = 30 + \frac{10 - 9}{5} \times 10 = 30 + \frac{1}{5} \times 10 = 32 Hence, **Option B** is the correct answer.

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