Central Tendency & DispersionPYQ Dec 22Question 2959 of 473
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The median of the observations 42,72,35,92,67,85,72,81,51,56\displaystyle 42, 72, 35, 92, 67, 85, 72, 81, 51, 56 is:

Options

A69.5\displaystyle 69.5
B72\displaystyle 72
C64\displaystyle 64
D61.5\displaystyle 61.5
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Correct Answer

✅ Option a — 69.5\displaystyle 69.5

All Options:

  • A69.5\displaystyle 69.5
  • B72\displaystyle 72
  • C64\displaystyle 64
  • D61.5\displaystyle 61.5

Detailed Solution & Explanation

We are given the observations: 42,72,35,92,67,85,72,81,51,56\displaystyle 42, 72, 35, 92, 67, 85, 72, 81, 51, 56. 1. Arrange the data in ascending order: 35,42,51,56,67,72,72,81,85,9235, 42, 51, 56, 67, 72, 72, 81, 85, 92 Here, the number of observations is n=10\displaystyle n = 10 (which is even). 2. The median is the average of the two middle-most values (the 5th\displaystyle 5^{\text{th}} and 6th\displaystyle 6^{\text{th}} terms): - 5th\displaystyle 5^{\text{th}} term: 67\displaystyle 67 - 6th\displaystyle 6^{\text{th}} term: 72\displaystyle 72 3. Calculate the median: Median=67+722=1392=69.5\text{Median} = \frac{67 + 72}{2} = \frac{139}{2} = 69.5 Hence, **Option A** is the correct answer.

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