Measures of Central Tendency and DispersionMCQMTP June 24 Series IIQuestion 2988 of 473
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Find Q1\displaystyle Q_1 for the following observations: 7,9,5,4,10,15,14,18,6,20\displaystyle 7,9,5,4,10,15,14,18,6,20

Options

A4.75\displaystyle 4.75
B5.25\displaystyle 5.25
C5.75\displaystyle 5.75
D6.25\displaystyle 6.25
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Correct Answer

Option c5.75\displaystyle 5.75

All Options:

  • A4.75\displaystyle 4.75
  • B5.25\displaystyle 5.25
  • C5.75\displaystyle 5.75
  • D6.25\displaystyle 6.25

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Detailed Solution & Explanation

To find the first quartile (Q1\displaystyle Q_1) for the observations: 7,9,5,4,10,15,14,18,6,20\displaystyle 7, 9, 5, 4, 10, 15, 14, 18, 6, 20: 1. Arrange the data in ascending order: 4,5,6,7,9,10,14,15,18,204, 5, 6, 7, 9, 10, 14, 15, 18, 20 Here, the number of observations is n=10\displaystyle n = 10. 2. The position of Q1\displaystyle Q_1 is given by: Position of Q1=n+14=10+14=2.75th observation\text{Position of } Q_1 = \frac{n+1}{4} = \frac{10+1}{4} = 2.75^{\text{th}} \text{ observation} 3. Calculate the value of the 2.75th\displaystyle 2.75^{\text{th}} observation: Q1=2nd observation+0.75×(3rd observation2nd observation)Q_1 = 2^{\text{nd}} \text{ observation} + 0.75 \times (3^{\text{rd}} \text{ observation} - 2^{\text{nd}} \text{ observation}) Q1=5+0.75×(65)=5+0.75×1=5.75Q_1 = 5 + 0.75 \times (6 - 5) = 5 + 0.75 \times 1 = 5.75 Hence, **Option C** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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