Measures of Central Tendency and DispersionMCQPYQ Dec 23Question 3039 of 473
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The AM and HM of two numbers are 5 and 3.2 respectively, then GM will be:

Options

A4.4
B4.2
C4.0
D3.8
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Correct Answer

✅ Option c — 4.0

All Options:

  • A4.4
  • B4.2
  • C4.0
  • D3.8

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Detailed Solution & Explanation

**Step 1: Recall the relationship AM × HM = GM².** GM2=AM×HM\text{GM}^2 = \text{AM} \times \text{HM} **Step 2: Substitute values.** - AM = 5, HM = 3.2 GM2=5×3.2=16\text{GM}^2 = 5 \times 3.2 = 16 GM=16=4.0\text{GM} = \sqrt{16} = 4.0 Hence, **Option C** is the correct answer.

About This Chapter: Measures of Central Tendency and Dispersion

Paper

Paper 3: Quantitative Aptitude

Weightage

12-15 Marks

Key Topics

Mean, Median, Mode, Range, Mean Deviation, Standard Deviation

The core foundation of Statistics. This chapter covers Mean (Arithmetic, Geometric, Harmonic), Median, Mode, and their properties. It also explores measures of spread like Range, Mean Deviation, Standard Deviation, and Quartile Deviation.

View Official ICAI Syllabus

Exam Strategy Tip

Do not just memorize formulas; ICAI loves asking about the mathematical properties (e.g., 'sum of deviations from the AM is always zero'). You can usually eliminate 2 options just by knowing the properties.

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