Mean and S.D. of x is 50 and 5 respectively. Find mean and S.D. of X = -50

Option b: (0, 1). Solution: Given: Mean of x = 50, SD of x = 5 Question asks for mean and SD of Z = x - 50/5 (this is implied by the standardization notation X = -50 likely means Z = (x-50)/5 based on context). Actually reading literally: Z = x - 50 - Mean of Z = Mean of x - 50 = 50 - 50 = 0 - SD of Z = SD of x = 5 (adding constant doesn't change SD) But (0, 5) is not in the options. This likely means Z = x - 50/5: - Mean of Z = 50 - 50/5 = 0 - SD of Z = 5/5 = 1 So (Mean, SD) = (0, 1) — this is Option B. Hence, Option B is the correct answer.

Mean and S.D. of $x$ is $50$ and $5$ respectively. Find mean and S.D. of $X = -50$

The correct answer is Option b: $(0, 1)$. **Given:** Mean of $x = 50$, SD of $x = 5$ **Question asks for mean and SD of $Z = \frac{x - 50}{5}$** (this is implied by the standardization notation $X = -50$ likely means $Z = (x-50)/5$ based on context). **Actually reading literally: $Z = x - 50$** - Mean of $Z$ = Mean of $x$ - 50 = 50 - 50 = **0** - SD of $Z$ = SD of $x$ = **5** (adding constant doesn't change SD) But $(0, 5)$ is not in the options. This likely means $Z = \frac{x - 50}{5}$: - Mean of $Z = \frac{50 - 50}{5} = 0$ - SD of $Z = \frac{5}{5} = 1$ So (Mean, SD) = **(0, 1)** — this is Option B. Hence, **Option B** is the correct answer.

Central Tendency & DispersionMTP June 24 Series IIQuestion 3211 of 473

All Questions

Mean and S.D. of $\displaystyle x$ is $\displaystyle 50$ and $\displaystyle 5$ respectively. Find mean and S.D. of $\displaystyle X = -50$

Options

\displaystyle (1, 0)

\displaystyle (0, 1)

\displaystyle (1, 1)

\displaystyle (0, -1)

For any discrepancies in this question, email contact@cadada.in

Correct Answer

✅ Option b — $\displaystyle (0, 1)$

All Options:

A $\displaystyle (1, 0)$
B $\displaystyle (0, 1)$
C $\displaystyle (1, 1)$
D $\displaystyle (0, -1)$

Detailed Solution & Explanation

**Given:** Mean of

\displaystyle x = 50

, SD of

\displaystyle x = 5

**Question asks for mean and SD of

\displaystyle Z = \frac{x - 50}{5}

** (this is implied by the standardization notation

\displaystyle X = -50

likely means

\displaystyle Z = (x-50)/5

based on context). **Actually reading literally:

\displaystyle Z = x - 50

** - Mean of

\displaystyle Z

= Mean of

\displaystyle x

- 50 = 50 - 50 = **0** - SD of

\displaystyle Z

= SD of

\displaystyle x

= **5** (adding constant doesn't change SD) But

\displaystyle (0, 5)

is not in the options. This likely means

\displaystyle Z = \frac{x - 50}{5}

: - Mean of

\displaystyle Z = \frac{50 - 50}{5} = 0

- SD of

\displaystyle Z = \frac{5}{5} = 1

So (Mean, SD) = **(0, 1)** — this is Option B. Hence, **Option B** is the correct answer.

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Mean and S.D. of x\displaystyle xx is 50\displaystyle 5050 and 5\displaystyle 55 respectively. Find mean and S.D. of X=−50\displaystyle X = -50X=−50