If the mean of frequency distribution is 100 and coefficient of variation is 45% then SD is

Option a: 45. Solution: Given: Mean = 100, CV = 45% Step 1: Use CV formula. CV = sigma/x-bar x 100 45 = sigma/100 x 100 sigma = 45 Result: SD = 45 Hence, Option A is the correct answer.

Central Tendency & DispersionMTP June 24 Series IIIQuestion 3212 of 473

All Questions

If the mean of frequency distribution is $\displaystyle 100$ and coefficient of variation is $\displaystyle 45\%$ then SD is

Options

\displaystyle 45

\displaystyle 0.45

\displaystyle 4.5

\displaystyle 450

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Correct Answer

✅ Option a — $\displaystyle 45$

All Options:

A $\displaystyle 45$
B $\displaystyle 0.45$
C $\displaystyle 4.5$
D $\displaystyle 450$

Detailed Solution & Explanation

**Given:** Mean = 100, CV = 45% **Step 1: Use CV formula.**

CV = \frac{\sigma}{\bar{x}} \times 100

45 = \frac{\sigma}{100} \times 100

\sigma = 45

**Result:** SD = **45** Hence, **Option A** is the correct answer.

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If the mean of frequency distribution is 100\displaystyle 100100 and coefficient of variation is 45%\displaystyle 45\%45% then SD is