Central Tendency & DispersionPYQ June 19Question 3217 of 473
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The Q.D of 6\displaystyle 6 numbers 15,8,36,40,38,41\displaystyle 15, 8, 36, 40, 38, 41 is

Options

A12.5\displaystyle 12.5
B25\displaystyle 25
C13.5\displaystyle 13.5
D37\displaystyle 37
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Correct Answer

✅ Option c — 13.5\displaystyle 13.5

All Options:

  • A12.5\displaystyle 12.5
  • B25\displaystyle 25
  • C13.5\displaystyle 13.5
  • D37\displaystyle 37

Detailed Solution & Explanation

We are given the observations: 15,8,36,40,38,41\displaystyle 15, 8, 36, 40, 38, 41. 1. Arrange the data in ascending order: 8,15,36,38,40,418, 15, 36, 38, 40, 41 Here, the number of observations is n=6\displaystyle n = 6. 2. Find the first quartile (Q1\displaystyle Q_1): - Position of Q1=6+14=1.75th\displaystyle Q_1 = \frac{6+1}{4} = 1.75^{\text{th}} term. - Q1=8+0.75×(15−8)=13.25\displaystyle Q_1 = 8 + 0.75 \times (15 - 8) = 13.25. 3. Find the third quartile (Q3\displaystyle Q_3): - Position of Q3=3(6+1)4=5.25th\displaystyle Q_3 = \frac{3(6+1)}{4} = 5.25^{\text{th}} term. - Q3=40+0.25×(41−40)=40.25\displaystyle Q_3 = 40 + 0.25 \times (41 - 40) = 40.25. 4. Calculate Quartile Deviation (Q.D.): Q.D.=Q3−Q12=40.25−13.252=272=13.5\text{Q.D.} = \frac{Q_3 - Q_1}{2} = \frac{40.25 - 13.25}{2} = \frac{27}{2} = 13.5 Hence, **Option C** is the correct answer.

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