Central Tendency & DispersionMTP March 22Question 3243 of 473
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If the quartile deviation of x\displaystyle x is 6\displaystyle 6 and 3x+6y=20\displaystyle 3x + 6y = 20, what is the quartile deviation of y\displaystyle y?

Options

A3\displaystyle 3
B4\displaystyle 4
C5\displaystyle 5
D6\displaystyle 6
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Correct Answer

✅ Option a — 3\displaystyle 3

All Options:

  • A3\displaystyle 3
  • B4\displaystyle 4
  • C5\displaystyle 5
  • D6\displaystyle 6

Detailed Solution & Explanation

We are given the relationship between variables x\displaystyle x and y\displaystyle y: 3x+6y=20  ⟹  6y=−3x+20  ⟹  y=−0.5x+1033x + 6y = 20 \implies 6y = -3x + 20 \implies y = -0.5x + \frac{10}{3} Since quartile deviation is independent of change of origin but affected by change of scale: Q.D.y=∣a∣×Q.D.x\text{Q.D.}_y = |a| \times \text{Q.D.}_x Substitute the given values (a=−0.5\displaystyle a = -0.5 and Q.D.x=6\displaystyle \text{Q.D.}_x = 6): Q.D.y=∣−0.5∣×6=0.5×6=3\text{Q.D.}_y = |-0.5| \times 6 = 0.5 \times 6 = 3 Hence, **Option A** is the correct answer.

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