Mathematics for FinanceMTP Jun 23 Series IIQuestion 3942 of 507
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If the compound interest on a certain sum of money for 2\displaystyle 2 years at 5%\displaystyle 5\% p.a. be 50.44\displaystyle 50.44, then the simple interest (S.I.) is

Options

A50\displaystyle 50
B49\displaystyle 49
C48\displaystyle 48
DNone of these
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Correct Answer

Option b49\displaystyle 49

All Options:

  • A50\displaystyle 50
  • B49\displaystyle 49
  • C48\displaystyle 48
  • DNone of these

Detailed Solution & Explanation

Let the principal be P\displaystyle P and the rate of interest be r=5%\displaystyle r = 5\% p.a. The compound interest (CI\displaystyle CI) on a sum of money for t\displaystyle t years is given by: CI=P[(1+r100)t1]CI = P\left[\left(1 + \frac{r}{100}\right)^t - 1\right] *Note: In the exam question, there is a typographical error in the time period. If we use t=2\displaystyle t = 2 years:* CI=P[(1.05)21]=P[1.10251]=0.1025PCI = P\left[(1.05)^2 - 1\right] = P[1.1025 - 1] = 0.1025P Given CI=50.44\displaystyle CI = 50.44: 0.1025P=50.44    P=50.440.1025492.100.1025P = 50.44 \implies P = \frac{50.44}{0.1025} \approx 492.10 Then the Simple Interest (SI\displaystyle SI) for 2\displaystyle 2 years would be: SI=P×r×t100=492.10×5×2100=49.21SI = \frac{P \times r \times t}{100} = \frac{492.10 \times 5 \times 2}{100} = 49.21 This value (49.21\displaystyle 49.21) corresponds to "None of these" (Option D). However, the textbook question was originally designed for t=3\displaystyle t = 3 years: CI=P[(1.05)31]=P[1.1576251]=0.157625PCI = P\left[(1.05)^3 - 1\right] = P[1.157625 - 1] = 0.157625P Given CI=50.44\displaystyle CI = 50.44: 0.157625P=50.44    P=50.440.157625=3200.157625P = 50.44 \implies P = \frac{50.44}{0.157625} = 320 Then the Simple Interest (SI\displaystyle SI) for 3\displaystyle 3 years is: SI=P×r×t100=320×5×3100=48SI = \frac{P \times r \times t}{100} = \frac{320 \times 5 \times 3}{100} = 48 Since Option C represents the intended answer of 48\displaystyle 48 using the corrected 3-year term, we follow this interpretation. Hence, **Option C** is the correct answer.

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