Ratio, Proportion, Indices, LogarithmsPYQ Jan 25Question 3943 of 215
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If x=2+12\displaystyle x = \sqrt{2} + \frac{1}{\sqrt{2}} and y=212\displaystyle y = \sqrt{2} - \frac{1}{\sqrt{2}} then x2+y2\displaystyle x^2 + y^2 is

Options

A2\displaystyle \sqrt{2}
B12\displaystyle \frac{1}{\sqrt{2}}
C5
D0
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Correct Answer

Option c5

All Options:

  • A2\displaystyle \sqrt{2}
  • B12\displaystyle \frac{1}{\sqrt{2}}
  • C5
  • D0

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