Linear InequalitiesPYQ Sept 25Question 4108 of 73
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The number of solutions of 52x4x85>32x\displaystyle \frac{5-2x}{4} \le \frac{x}{8} - 5 > 3-2x are ___________, where x\displaystyle x is a real number.

Options

AInfinitely many
BOnly two
CExactly one
DNo solution
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Correct Answer

Option aInfinitely many

All Options:

  • AInfinitely many
  • BOnly two
  • CExactly one
  • DNo solution

Detailed Solution & Explanation

We need to find the number of real solutions to the compound inequality: 52x4x85>32x\frac{5-2x}{4} \le \frac{x}{8} - 5 > 3-2x
This can be split into two separate inequalities: 1) 52x4x85\displaystyle \frac{5-2x}{4} \le \frac{x}{8} - 5 2) x85>32x\displaystyle \frac{x}{8} - 5 > 3-2x
Let us solve the first inequality: 52x4x85\frac{5-2x}{4} \le \frac{x}{8} - 5 Multiply both sides by 8 to clear the denominators: 2(52x)x402(5 - 2x) \le x - 40 104xx4010 - 4x \le x - 40 505x    x1050 \le 5x \implies x \ge 10
Now let us solve the second inequality: x85>32x\frac{x}{8} - 5 > 3-2x Multiply both sides by 8: x40>8(32x)x - 40 > 8(3 - 2x) x40>2416xx - 40 > 24 - 16x 17x>64    x>64173.7617x > 64 \implies x > \frac{64}{17} \approx 3.76
Finding the intersection of x10\displaystyle x \ge 10 and x>3.76\displaystyle x > 3.76: x10x \ge 10 Since x\displaystyle x is a real number, there are infinitely many real values of x\displaystyle x in the interval [10,)\displaystyle [10, \infty) that satisfy this compound inequality.
Hence, **Option A** is the correct answer.

About This Chapter: Linear Inequalities

Paper

Paper 3: Quantitative Aptitude

Weightage

1-3 Marks

Key Topics

Linear Inequalities in one & two variables

This chapter covers Linear Inequalities in one & two variables and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 1-3 Marks weightage. Focus on understanding core concepts rather than memorizing.

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