Correct Answer
✅ Option c — 2880
All Options:
- A720
- B1440
- C2880
- D2160
Detailed Solution & Explanation
The word has 8 positions, numbered 1 to 8 from left to right. - Odd positions: 1, 3, 5, 7 (Total of 4 odd positions) - Even positions: 2, 4, 6, 8 (Total of 4 even positions)
According to the condition, the vowels must occupy odd positions. - We have 3 vowels and 4 odd positions. The number of ways to place the 3 vowels in the 4 odd positions is:
- The remaining 5 positions (1 odd position and 4 even positions) will be occupied by the 5 consonants. The number of ways to arrange the 5 consonants in these 5 positions is:
The total number of words that can be formed is:
Hence, **Option C** is the correct answer.
About This Chapter: Permutations and Combinations
Paper
Paper 3: Quantitative Aptitude
Weightage
4-6 Marks
Key Topics
Factorials, Permutations, Combinations
This chapter deals with the fundamental principles of counting. It covers factorials, circular permutations, restricted permutations, combinations, and the differences between selecting items versus arranging them.
View Official ICAI SyllabusExam Strategy Tip
The most common mistake is confusing 'P' (Arrangement) with 'C' (Selection). If order matters (like opening a lock), use P. If order doesn't matter (like choosing a team), use C.
More Questions from Permutations and Combinations
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A person can go from place 'A' to 'B' by 11 different modes of transport but is allowed to return to 'A' by any mode other than the one earlier. The number of different ways in which the entire journey can be completed is:
If a man travels from place A to B in 10 ways then by how many ways can he come back by another train?
If find 'n'.
Which of the following is a correct statement.
. Find .
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