A father had three sons namely, Kailash, Harish and Prakash. All are above 65 years in age. Prakash happens to be the eldest while Kailash as youngest. As per the health history, it is estimated that the probability that Kailash survives another 5 years is 4/5, Harish survives another 5 years is 3/5 and Prakash survives another 5 years is 1/2. The probabilities that Kailash and Harish survive another 5 years is 0.46, Harish and Prakash survive another 5 years is 0.32 and Kailash and Prakash survive another 5 years is 0.48. The probability that all three sons survive another 5 years is 0.26. What shall be the probability that at least one of them survives another 5 years?

According to bayee's theorem, $\displaystyle P(E_i / A) = \frac{P(E_i)P(A / E_i)}{\sum_{j=1}^{n} P(E_j)P(A / E_j)}$ here

When $\displaystyle 2$ - dice are thrown simultaneously then the probability of getting at least one $\displaystyle 5$ is

A log contains $\displaystyle 15$ one rupee coins, $\displaystyle 25$ two rupees coins and $\displaystyle 10$ five rupee coins if a coin is selected at random than probability for not selecting a one rupee coin is:

What is the probability of occurring $\displaystyle 4$ or more than $\displaystyle 4$ accidents.No. of acc. | Frequency0 | 361 | 272 | 233 | 244 | 245 | 276 | 187 | 9

When two coins are tossed simultaneously the probability of getting at least one tail?

Two broad divisions of probability are