Ratio, Proportion, Indices, LogarithmPYQ Nov 18Question 788 of 211
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3x2:5x+6\displaystyle 3x-2:5x+6 the duplicate ratio of 2:3\displaystyle 2:3 then find the value x\displaystyle x.

Options

A2\displaystyle 2
B6\displaystyle 6
C5\displaystyle 5
D9\displaystyle 9
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Correct Answer

Option b6\displaystyle 6

All Options:

  • A2\displaystyle 2
  • B6\displaystyle 6
  • C5\displaystyle 5
  • D9\displaystyle 9

Detailed Solution & Explanation

• The problem states that the ratio 3x2:5x+6\displaystyle 3x-2:5x+6 is the duplicate ratio of 2:3\displaystyle 2:3. • First, let's understand what a duplicate ratio is. The duplicate ratio of a:b\displaystyle a:b is a2:b2\displaystyle a^2:b^2. • So, the duplicate ratio of 2:3\displaystyle 2:3 is 22:32\displaystyle 2^2:3^2. • Calculating this, we get 22=4\displaystyle 2^2 = 4 and 32=9\displaystyle 3^2 = 9. So, the duplicate ratio is 4:9\displaystyle 4:9. • Now, we are given that 3x2:5x+6\displaystyle 3x-2:5x+6 is equal to this duplicate ratio. Therefore, we can write the equation: 3x25x+6=49\displaystyle \frac{3x-2}{5x+6} = \frac{4}{9}. • To solve for x\displaystyle x, we cross-multiply: 9(3x2)=4(5x+6)\displaystyle 9(3x-2) = 4(5x+6). • Distribute the numbers on both sides of the equation: 27x18=20x+24\displaystyle 27x - 18 = 20x + 24. • Now, we need to gather the x\displaystyle x terms on one side and the constant terms on the other side. Subtract 20x\displaystyle 20x from both sides: 27x20x18=24\displaystyle 27x - 20x - 18 = 24. 7x18=24\displaystyle 7x - 18 = 24. • Add 18\displaystyle 18 to both sides: 7x=24+18\displaystyle 7x = 24 + 18. 7x=42\displaystyle 7x = 42. • Finally, divide by 7\displaystyle 7 to find the value of x\displaystyle x: x=427\displaystyle x = \frac{42}{7}. x=6\displaystyle x = 6. • The correct answer is 6\displaystyle 6. • Option (B) is 6\displaystyle 6, which matches our calculated value for x\displaystyle x. This is why it is the correct answer. • Option (A) is 2\displaystyle 2. If x=2\displaystyle x=2, then 3(2)25(2)+6=6210+6=416=14\displaystyle \frac{3(2)-2}{5(2)+6} = \frac{6-2}{10+6} = \frac{4}{16} = \frac{1}{4}. This is not equal to 49\displaystyle \frac{4}{9}. So, 2\displaystyle 2 is incorrect. • Option (C) is 5\displaystyle 5. If x=5\displaystyle x=5, then 3(5)25(5)+6=15225+6=1331\displaystyle \frac{3(5)-2}{5(5)+6} = \frac{15-2}{25+6} = \frac{13}{31}. This is not equal to 49\displaystyle \frac{4}{9}. So, 5\displaystyle 5 is incorrect.

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

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Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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