The mean proportional between 12x2 and 27y2 is:

Option b: 18xy. Solution: The mean proportional between two algebraic terms a and b is defined as sqrt(a × b) . For the terms 12x2 and 27y2 , we calculate: Mean Proportional = sqrt(12x2 × 27y2) = sqrt(324 x2 y2) = 18xy

The mean proportional between $12x^2$ and $27y^2$ is:

The correct answer is Option b: $18xy$. The mean proportional between two algebraic terms $a$ and $b$ is defined as $\sqrt{a \cdot b}$. For the terms $12x^2$ and $27y^2$, we calculate: $$\text{Mean Proportional} = \sqrt{12x^2 \times 27y^2}$$ $$= \sqrt{324 x^2 y^2} = 18xy$$

Ratio, Proportion, Indices, LogarithmMCQPYQ Sep 24Question 811 of 305

All Questions

The mean proportional between $\displaystyle 12x^2$ and $\displaystyle 27y^2$ is:

Options

\displaystyle 81xy

\displaystyle 18xy

\displaystyle 8xy

\displaystyle 19.5xy

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Correct Answer

✅ Option b — $\displaystyle 18xy$

All Options:

A $\displaystyle 81xy$
B $\displaystyle 18xy$
C $\displaystyle 8xy$
D $\displaystyle 19.5xy$

Detailed Solution & Explanation

The mean proportional between two algebraic terms

\displaystyle a

and

\displaystyle b

is defined as

\displaystyle \sqrt{a \cdot b}

.
For the terms

\displaystyle 12x^2

and

\displaystyle 27y^2

, we calculate:

\text{Mean Proportional} = \sqrt{12x^2 \times 27y^2}

= \sqrt{324 x^2 y^2} = 18xy

About This Chapter: Ratio, Proportion, Indices, Logarithm

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Ratio, Proportion, Indices, Logarithms

This chapter covers Ratio, Proportion, Indices, Logarithms and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 5-7 Marks weightage. Focus on understanding core concepts rather than memorizing.

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The mean proportional between 12x2\displaystyle 12x^212x2 and 27y2\displaystyle 27y^227y2 is: