No. of accidents | Frequency---|--- 0 | $36 1 | $27 2 | $33 3 | $29 4 | $24 5 | $22 6 | $18$ 7 | 9 In how many cases 5 or more accidents occur?

Question

Accepted Answer

Option d: $54$. Solution: We need to find the number of cases where 5 or more accidents occur. This is the sum of frequencies for 5 , 6 , and 7 accidents. Based on the standard frequency distribution data (where the frequency of 5 accidents is $27 , which was misparsed as $22 due to a PDF parsing issue): - Frequency of 5 accidents = $27$ - Frequency of 6 accidents = $18$ - Frequency of 7 accidents = 9 Summing these frequencies: Number of cases = 27 + 18 + 9 = 54 This matches Option D. Hence, Option D is the correct answer.

No. of accidents | Frequency---|--- $\displaystyle 0$ | $36 $\displaystyle 7$

Correct Answer

All Options:

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No. of accidents | Frequency---|---0\displaystyle 00 | $361\displaystyle | &#36;27</span>2 | $333\displaystyle | &#36;29</span>4 | $245\displaystyle | &#36;22</span>6 | $18$7\displaystyle 77 | 9\displaystyle 99In how many cases 5\displaystyle 55 or more accidents occur?