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The following table gives the expected value of follow. distribution | P(X) | -20 | -10 | 30 | 75 | 80 ||---|---|---|---|---|---|| P(X) | 320\displaystyle \frac{3}{20} | 15\displaystyle \frac{1}{5} | 12\displaystyle \frac{1}{2} | 110\displaystyle \frac{1}{10} | 120\displaystyle \frac{1}{20} | Find the Expected value of follow. distribution

Select Your Answer (Keyboard: A, B, C, D)
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Correct Answer

✅ Option b — $21.5$

All Options:

  • A$20.5$
  • B$21.5$
  • C$22.8$
  • D$24.5$

Detailed Solution & Explanation

Let's calculate the expected value E(X)=∑xiP(xi)\displaystyle E(X) = ∑\displaystyle \sum x_i P(x_i). From the given probability distribution table: - Values of X\displaystyle X: −20,−10,30,75,80\displaystyle -20, -10, 30, 75, 80 - Probabilities P(X)\displaystyle P(X): 320,15,12,110,120\displaystyle 320\displaystyle \frac{3}{20}, 15\displaystyle \frac{1}{5}, 12\displaystyle \frac{1}{2}, 110\displaystyle \frac{1}{10}, 120\displaystyle \frac{1}{20} E(X)=(−20×320)+(−10×15)+(30×12)+(75×110)+(80×120)\displaystyle E(X) = \left(-20 ×\displaystyle \times 320\displaystyle \frac{3}{20}\right) + \left(-10 ×\displaystyle \times 15\displaystyle \frac{1}{5}\right) + \left(30 ×\displaystyle \times 12\displaystyle \frac{1}{2}\right) + \left(75 ×\displaystyle \times 110\displaystyle \frac{1}{10}\right) + \left(80 ×\displaystyle \times 120\displaystyle \frac{1}{20}\right) E(X)=−3−2+15+7.5+4\displaystyle E(X) = -3 - 2 + 15 + 7.5 + 4 E(X)=21.5\displaystyle E(X) = 21.5. Hence, **Option B** is the correct answer.

About This Chapter: Probability

Paper

Paper 3: Quantitative Aptitude

Weightage

5-7 Marks

Key Topics

Probability Operations, Expected Value

A logic-heavy chapter dealing with random experiments, events (mutually exclusive, exhaustive), set theory probability, conditional probability, and Bayes' Theorem. It forms the basis for Theoretical Distributions.

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Exam Strategy Tip

Always draw a quick Venn Diagram or tree when faced with 'At least one' or 'Only A but not B' wording. It saves you from double-counting.

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