The age of a man is four times the sum of the ages of his two sons and after 10 years, his age will be double the sum of their ages. The present age of the man must be
Correct Answer
✅ Option c — 60 years
All Options:
- A56 years
- B45 years
- C60 years
- D64 years
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Detailed Solution & Explanation
According to the first condition:
After 10 years, the man's age will be years.
Since there are two sons, each of their ages increases by 10 years, so the sum of their ages increases by years. The sum of the sons' ages after 10 years will be years.
According to the second condition:
Substitute Equation 1 () into Equation 2:
Now, find the present age of the man :
Thus, the present age of the man is 60 years.
**Correct Option: (c)**
About This Chapter: Equations
Paper
Paper 3: Quantitative Aptitude
Weightage
4-6 Marks
Key Topics
Linear, Quadratic and Cubic Equations
This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.
View Official ICAI SyllabusExam Strategy Tip
This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.
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