EquationsMCQPYQ Dec 23Question 1012 of 221
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Divide 27 into two parts, so that 5 times the first and 11 times the second together equal to 195, then the ratio of first and second part is:

Chapter 2 Diagram

Options

A17:10\displaystyle 17:10
B15:12\displaystyle 15:12
C14:13\displaystyle 14:13
D16:11\displaystyle 16:11
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Correct Answer

Option a17:10\displaystyle 17:10

All Options:

  • A17:10\displaystyle 17:10
  • B15:12\displaystyle 15:12
  • C14:13\displaystyle 14:13
  • D16:11\displaystyle 16:11

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Detailed Solution & Explanation

Let the first part be x\displaystyle x and the second part be y\displaystyle y.
Since 27 is divided into two parts:
x+y=27— (Equation 1)x + y = 27 \quad \text{--- (Equation 1)}
According to the second condition:
5x+11y=195— (Equation 2)5x + 11y = 195 \quad \text{--- (Equation 2)}
From Equation 1, we can express x\displaystyle x as x=27y\displaystyle x = 27 - y. Substitute this into Equation 2:
5(27y)+11y=1955(27 - y) + 11y = 195
1355y+11y=195135 - 5y + 11y = 195
6y=1951356y = 195 - 135
6y=60    y=106y = 60 \implies y = 10
Now find x\displaystyle x:
x=2710=17x = 27 - 10 = 17
So the first part is 17 and the second part is 10.
The ratio of the first part to the second part is:
x:y=17:10x:y = 17:10
**Correct Option: (a)**

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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