The age of a person is twice the sum of the ages of his two sons and 5 years ago his age was thrice the sum of their ages. Find present age.
Correct Answer
✅ Option d — 50 years
All Options:
- A60 years
- B52 years
- C51 years
- D50 years
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Detailed Solution & Explanation
According to the first condition:
5 years ago:
- The person's age was years.
- The sum of the ages of his two sons was years (since each son's age decreases by 5 years).
According to the second condition:
Substitute Equation 1 () into Equation 2:
Now find the present age of the person :
Thus, the person's present age is 50 years.
*(Note: The input key of 'b' (52) is incorrect. The mathematically correct answer is 50, option D.)*
**Correct Option: (d)**
About This Chapter: Equations
Paper
Paper 3: Quantitative Aptitude
Weightage
4-6 Marks
Key Topics
Linear, Quadratic and Cubic Equations
This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.
View Official ICAI SyllabusExam Strategy Tip
This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.
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