EquationsMCQMTP Nov 20Question 1023 of 221
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The cost of 5 mangoes is equal to the cost of 20 oranges. If the total cost 2 mangoes and 10 oranges is 22.50\displaystyle 22.50, find the cost of two oranges.

Chapter 2 Diagram

Options

A1.25\displaystyle 1.25
B2.50\displaystyle 2.50
C3\displaystyle 3
D3.50\displaystyle 3.50
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Correct Answer

Option b2.50\displaystyle 2.50

All Options:

  • A1.25\displaystyle 1.25
  • B2.50\displaystyle 2.50
  • C3\displaystyle 3
  • D3.50\displaystyle 3.50

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Detailed Solution & Explanation

Let the cost of a mango be m\displaystyle m and the cost of an orange be o\displaystyle o.
According to the first condition:
5m=20o    m=4o5m = 20o \implies m = 4o
According to the second condition:
2m+10o=22.502m + 10o = 22.50
Substitute m=4o\displaystyle m = 4o into the second equation:
2(4o)+10o=22.502(4o) + 10o = 22.50
8o+10o=22.508o + 10o = 22.50
18o=22.5018o = 22.50
o=22.5018=1.25o = \frac{22.50}{18} = 1.25
Thus, the cost of one orange is 1.25\displaystyle 1.25.
We need to find the cost of two oranges (2o\displaystyle 2o):
Cost of 2 oranges=2×1.25=2.50\text{Cost of 2 oranges} = 2 \times 1.25 = 2.50
*(Note: The input key of 'd' (3.50) is incorrect. The mathematically correct choice is 2.50, option B.)*
**Correct Option: (b)**

About This Chapter: Equations

Paper

Paper 3: Quantitative Aptitude

Weightage

4-6 Marks

Key Topics

Linear, Quadratic and Cubic Equations

This chapter covers Linear, Quadratic and Cubic Equations and is part of Paper 3: Quantitative Aptitude in the CA Foundation exam.

View Official ICAI Syllabus

Exam Strategy Tip

This topic carries 4-6 Marks weightage. Focus on understanding core concepts rather than memorizing.

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