A box contains $56$ in the form of coins of one rupee, 50 paise and 25 paise. The number of 50 paise coin is double the number of 25 paise coins and four times the numbers of one rupee coins. The numbers of 50 paise coins in the box is

If $\sqrt{\frac{1}{25}} = 1 + \frac{x}{144}$, then $x$ is

If $\frac{3}{x+y} + \frac{2}{x-y} = -1$ and $\frac{1}{x+y} - \frac{1}{x-y} = \frac{4}{3}$ then $(x, y)$ is:

$\frac{2x+5}{10} + \frac{3x+10}{15} = 5$, find $x$

Find value of $x^2 - 10x + 1$ if $x = \frac{1}{5-2\sqrt{6}}$

In a multiple choice question paper consisting of $100$ questions of $1$ mark each, a candidate gets $60\%$ marks. If the candidate attempted all questions and there was a penalty of $0.25$ marks for wrong answers is:

The solution of the following system of linear eqs. $2x - 5y + 4 = 0$ and $2x + y - 8 = 0$ will be: